Question

prove that the tangent at any point of a circle is perpendicular to the radius through the point of contract​

Answer 1

Step-by-step explanation:

Construction : Take a point B, other than A, on the tangent l. ... Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is shortest to l. OA = OC (Radius of the same circle) Now, OB = OC + BC.

Answer 2

Answer:

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Step-by-step explanation:

see...the pic .....then u can understand it