Question

Prove that the tangent at any point of the circle is perpendicular to the radius through the point of contact ..... No irrelevant answers ​

Answer 1

Answer:

Thats it!!

Don't mind my handwriting..

Hope it helps u mam..

Answer 2

Step-by-step explanation:

$Referring to the figure:</p><p></p><p></p><p>OA=OC (Radii of circle)</p><p></p><p></p><p>Now OB=OC+BC</p><p></p><p></p><p>∴OB>OC    (OC being radius and B any point on tangent)</p><p></p><p></p><p>⇒OA<OB</p><p></p><p></p><p>B is an arbitrary point on the tangent. </p><p></p><p></p><p>Thus, OA is shorter than any other line segment joining O to any </p><p></p><p>point on tangent.</p><p></p><p></p><p>Shortest distance of a point from a given line is the perpendicular distance from that line.</p><p></p><p></p><p>Hence, the tangent at any point of circle is perpendicular to the radius.</p><p></p><p>$

Mark as Brainlist