Question

prove that the tangent at any points of the circoe is perpendicular to the radius,through the point of contact​

Answer 1

Answer:

With

Step-by-step explanation:

Referring to the figure in the attachment

OA=OC OA=OC (Radii of circle)

Now OB =OC+BC OB=OC+BC

\therefore OB > OC∴OB>OC (OCOC being radius and BB any point on tangent)

→ OA < OB⇒OA<OB

BB is an arbitrary point on the tangent.

Thus, OAOA is shorter than any other line segment joining OO to any

point on tangent.

Shortest distance of a point from a given line is the perpendicular distance from that line.

Hence, the tangent at any point of circle is perpendicular to the radius.

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Answer 2

Hope this helps you. .

- Khushali.S.S. .