Prove that the tangent drawn at the mid point of an arc of a circle is parallel to the chord joining the end points of the arc.
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Let XY be the tangent at the mid point of the arc A
Let TT be the point of contact

Let ABAB be the chord
Since T is the mid point , Distance mid point of AB.
Construction join OA ,OB and OT , where O is the centre of the circle .
Proof : ∠OTY=90∘∠OTY=90∘
∠ODB=90∘∠ODB=90∘
Since the alternate interior angles are equal.
ABAB is parallel to xy
Let TT be the point of contact

Let ABAB be the chord
Since T is the mid point , Distance mid point of AB.
Construction join OA ,OB and OT , where O is the centre of the circle .
Proof : ∠OTY=90∘∠OTY=90∘
∠ODB=90∘∠ODB=90∘
Since the alternate interior angles are equal.
ABAB is parallel to xy
MrMad:
can u plzz upload a diagram of this ans.
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