⚡⚡prove that the tangent drawn from a common point are equal.
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ANSWERS :-
In triangle OBP and triangle OAP
OB = OA = r
<OBP = <OAP = 90°
OP = OP (BY COMMON)
So,
triangle OBP Congurent triangle by RHS creteria of congurence.
So,
BP = AP ( BY C.P.C.T )
Hence,
tangents from by a common points are equal in length.
________________________
❤BE BRAINLY ❤
_______________
In triangle OBP and triangle OAP
OB = OA = r
<OBP = <OAP = 90°
OP = OP (BY COMMON)
So,
triangle OBP Congurent triangle by RHS creteria of congurence.
So,
BP = AP ( BY C.P.C.T )
Hence,
tangents from by a common points are equal in length.
________________________
❤BE BRAINLY ❤
_______________
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hey mate..
To prove PT=QTPT=QT
Proof: Consider the triangle OPTOPT and OQTOQT.
OP=OQOP=OQ
∠OPT=∠OQT=90∘∠OPT=∠OQT=90∘
OT=OTOT=OT (common side)
Hence by RHS the triangles are equal.
Hence PT=QTPT=QT
Hence Proved.
To prove PT=QTPT=QT
Proof: Consider the triangle OPTOPT and OQTOQT.
OP=OQOP=OQ
∠OPT=∠OQT=90∘∠OPT=∠OQT=90∘
OT=OTOT=OT (common side)
Hence by RHS the triangles are equal.
Hence PT=QTPT=QT
Hence Proved.
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