prove that the tangent drawn from an exterior point to a circle are equal
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Given
= Let,R is the external point of circle
=From R two tangent are drawn to circle. And
P and Q are point of contact.
= Let , O is the center of circle
To prove : PR= QR
Construction : I join OP , OQ and
RO
Prove
Now in ∆ PRO and ∆ QRO
a. Angle RPO = Angle RQO (by theorem radii
always perpendicular
to tangent )
b. side Po = side QO (radii of same circle)
c. side RO = side RO ( common)
so by R.H.S ∆PRQ ≅ ∆QRO
Hence by C.P.C.T RP = RQ ----- proved
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