Question

Prove that “ the tangent drawn from an external point to a circle are eqaul”.​

Answer 1

Answer:

sorry...

Explanation:

I don't know that..

Answer 2

Explanation:

Given - A circle with centre O .

Take a point P.

Take two tangents from P - AP and BP

To prove - AP = BP

Proof - Now join OP

In triangle AOP and triangle BOP,

AO = BO ( radii of same circle )

OP = OP ( common )

angle OAP = angle OBP ( Each = 90 )

( Tangents are perpendicular to radius of a circle )

Therefore , triangle AOP is congruent to triangle BOP ( by RHS congruency )

By CPCT , AP= BP