Prove that “ the tangent drawn from an external point to a circle are eqaul”.
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Two tangents AP and AQ are drawn from a point A to a circle with centre O.
- AP = AQ
join OP ,OQ and OA .
AP is a tangent at P and OP is the radius through P.
∴ OP ⟂ AP
Similarly, OQ ⟂ AQ
In the right ∆ OPA and OQA
OP = OQ ( radii of the same circle )
OA = OA ( common )
∠ OPA = ∠OQA ( since AP and AQ are tangent to the circle )
∴ ∆OPA ≅ ∆ OQA ( by RHS congruence )
Hence, AP = AQ
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