Question

prove that the tangent drawn from an external point to equal
please explain step by step ​

Answer 1

Explanation:

and QT are two tangents drawn from an external point T to the circle C(O,r).

To Prove: PT=TQ.

∴∠OPT=∠OQT=90∘

∠OPT=∠OQT(90∘)

OT=OT (common)

OP=OQ (Radius of the circle)

∴△OPT≅△OQT (By RHS criterin)

So, PT=QT (By CPCT)