Question

prove that "the tangent drawn to a circle from an external point are equal"​

Answer 1

Answer:

refer to this attachment

Explanation:

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Answer 2

Answer:

To Prove : AP = BP

Proof :

In ΔAOP and ΔBOP

OA = OB (radii of the same circle)

∠OAP=∠OBP=90∘  (since tangent at any point of a circle is perpendicular to the radius through the point of contact)

OP = OP (common)

∴ΔAOP≅ΔOBP  (by R.H.S. congruence criterion)

∴ AP = BP  (corresponding parts of congruent triangles)

Hence the length of the tangents drawn from an external point to a circle are equal.

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