Prove that the tangent drawn to the end points of a chord of circle make equal angle with the chord
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FIGURE IS IN THE ATTACHMENT
Let AB be a chord of a circle with center O and let AP and BP be the tangents at A
and B.
Let the tangent meet at P.Join OP Suppose OP meets AB at C.
To prove : ZPAC = ZPBC
Proof: In APAC and APBC
PA = PB [Tangents from an external point to a circle are equal]
ZAPCO = Z PC [PA and PB are equally = inclined to OP]
PC = PC [Common]
APAC = APBC [SAS Congruence]
ZPAC = ZPBC [C.P.C.T]
HOPE THIS WILL HELP YOU....
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