prove that the tangents at the end points of a diameter are parallel
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Answered by
1
Step-by-step explanation:
Given:In c(o, r)
XY and X'Y' are tangents,
A and B are point of contact,
OA=OB
To prove:XY is parallel to X'Y'
Proof:we know that
OA is perpendicular to XY,
and OB is perpendicular to X'Y'
Angle XAO =Angle X'BO (each 90°)
hence,XY is perpendicular to X'Y'
Answered by
0
Step-by-step explanation:
Let AB be a diameter of the circle. Two tangents PQ and RS are drawn at points A and B respectively. Radius drawn to these tangents will be perpendicular to the tangents. Since alternate interior angles are equal, lines PQ and RS will be parallel.
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