Prove that the tangents dawn an external point to a circle are equal
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Hi mate here is the answer:--✍️✍️
Question:✔️
Prove that the length of tangents drawn from an external point to a circle are equal.
Solution:✔️
Let’s take PQ and PR, are the tangents drawn from an external point P to a circle with centre O.
To prove:
PR = PQ
Construction:
Join O to P, R and Q
It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.
OR ⟘ PR and OQ ⟘ PQ ... (i)
Proof: In ∆ORP and ∆OQP
OR = OQ (Radius of same circle)
OP = OP (Common)
∠ORP = ∠OQP (Each 90°)
∴ ∆ORP ≅ ∆OQP (R.H.S)
∴ PR = PQ
Corresponding parts of congruent triangles are equal.
Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal.
Hope it helps you ❣️☑️☑️
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