Prove that the tangents drawn at ends of a diameter
of a circle are equal
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Answer:
Given :
CD and EF are the tangents at the ned points A and B of the diameter AB of a circle with centre O.
To prove :CD∥EF.
Proof :
CD is the tangent to the circle at the point A.
Therefore, ∠BAD=90°
EF is the tangent to the circle at the point B.
Therefore, ∠ABE=90 °
Thus, ∠BAD=∠ABE=90°
But, these are alternate interior angles.
Therefore, CD∥EF.
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