Prove that the tangents drawn at the end of a diameter of a circle are parallel.
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Step-by-step explanation:
To prove: PQ||∣∣ RS
Given: A circle with centre O and diameter AB. Let PQ be the tangent at point A & Rs be the point B.
Proof: Since PQ is a tangent at point A.
OA\perp⊥ PQ(Tangent at any point of circle is perpendicular to the radius through point of contact).
\angle OQP=90^o∠OQP=90
o
…………(1)(1)
OB\perp⊥ RS
\angle OBS=90^o∠OBS=90
o
……………(2)(2)
From (1)(1) & (2)(2)
\angle OAP=\angle OBS∠OAP=∠OBS
i.e., \angle BAP=\angle ABS∠BAP=∠ABS
for lines PQ & RS and transversal AB
\angle BAP=\angle ABS∠BAP=∠ABS i.e., both alternate angles are equal.
So, lines are parallel.
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