prove that the tangents drawn at the end of a diameter of a circle are parallel
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I think it is a good question ...but I couldn't find answer sorry...
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Step-by-step explanation:
OA is perpendicular to MN
OB is also perpendicular to QP
<OAM=90°
<OAN=90°
<OBQ=90°
<OAM=<OBP(alternate angles)
<OAN=<OBQ( " )
Interior two angles are alternate, so MN//QP
Hence proved
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