Prove that the tangents drawn at the end points of a chord of a circle make equal angles with the chord.
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Consider two triangles ΔAPR and ΔAQR
the sides AP = AQ ( as because tangents drawn from an internal point to a circle are equal]
The angles ∠PAR and ∠QAR are equal
AR = AR [Common side]
∴ ΔAPR ≅ ΔAQR (using side angle side congruency.)
Hence ∠APR = ∠AQR (hence proved)
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r u from SSC board Maharashtra??????
KyloRen314:
its not about board harshada
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