Prove that the tangents drawn at the end points of a chord of a circle
make equal angles with the chord
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Consider a circle with centre, O and the chord PQ.
Tangents PT and QT meet at T.
OPQ is an isosceles triangle so that <PQO = <QPO = x. say.
<TPO = <TQO = 90 deg as PT and QT are tangents.
<TPQ = <TQP = 90 - x being complementary to the equal angles of the isosceles triangle OPQ.
Hence the tangents drawn at the ends of a chord of a circle make equal angles with the chord. Proved.
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