Prove that the tangents drawn at the ends of a diameter of a circle are parallel
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tangent is perpendicular to its radius...
then diameter is 2 time of radius
then the angle made but both the tangent is 90°
that means the tangents are parallel, interior angles sum is 180 on same side...
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Proved that,
Tangent AB ∥ tangent CD
Step-by-step explanation:
To prove:
Tangent AB ∥ tangent CD
Proof:
In a circle with centre O, OM ⊥ ON are the radii and AB and CD are the tangents respectively.
∴ By the theorem 10.1 which states that tangent at any point of a circle is perpendicular to the radius through the point of contact.
OM ⊥ AB and OM ⊥ OD
∴ ∠OMA = 90° and ∠OND = 90°
∴ ∠OMA = ∴ ∠OND
But, this is a pair of alternate angles,
∴ By alternate angle test for parallel lines,
AB ∥ CD
∴ Tangent AB ∥ tangent CD
Hence, the proof.
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