Prove that the tangents drawn at the ends of a diameter of a circle are parallel
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≡QUESTION≡
Prove that the tangents drawn at the ends of a diameter of a circle are parallel
║⊕ANSWER⊕║
OA ⊥ RS and OB ⊥ PQ
(Tangent at any point of circle is perpendicular to the radius through point of contact).
∠OAR = 90º
∠OAS = 90º
∠OBP = 90º
∠OBQ = 90º
=>
∠OAR = ∠OBQ (Alternate interior angles)
∠OAS = ∠OBP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel
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