Math, asked by siddharthchudas, 1 year ago

prove that the tangents drawn at the ends of a diameter of a circle are parallel

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Answered by NamaBhai
9
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Answered by xItzKhushix
17

\huge{\red{\underline{\mathfrak{Explanation:}}}}

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We have to prove that the tangents drawn at the ends of a diameter of a circle are parallel.

So, we will draw a circle and connect two points A and B such that AB becomes the diameter of the circle.

Now, we will draw two tangents PQ and RS at points A and B respectively.

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Now, both radii i.e. AO and OP are perpendicular to the tangents.

So, OB is perpendicular to RS and OA perpendicular to PQ

So, ∠OAP = ∠OAQ = ∠OBR = ∠OBS = 90°

From the above figure, angles OBR and OAQ are alternate interior angles.

Also, ∠OBR = ∠OAQ and ∠OBS = ∠OAP (As they are also alternate interior angles)

So, it can be said that line PQ and the line RS will be parallel to each other.

\huge{\blue{\mathfrak{Hence,Proved}}}

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