prove that the tangents drawn at the ends of a diameter of a circle are parallel .
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in the questions ,
here we let AB is a diameter. of the this circle and LM and PQ are the tangents line's drawn to in the circle at points A and B such as respectively.
To prove Lm || PQ
proof
all of you know that the tangents of any point an circle is perpendicular to their radius through the point of contact.
so ,
OA perpendicular PQ.
and ,
OB perpendicular LM
=> AB perpendicular PQ
and
AB perpendicular LM
=> Angle PAB = 90°
and ,
Angle ABM = 90°
=> Angle PAB = Angle ABM [ each 90°]
But these are alternate angles
so ,
PQ || LM
therefore the tangents drawn at the ends of a diameter of a circle are parallel.
proved
be brainly
here we let AB is a diameter. of the this circle and LM and PQ are the tangents line's drawn to in the circle at points A and B such as respectively.
To prove Lm || PQ
proof
all of you know that the tangents of any point an circle is perpendicular to their radius through the point of contact.
so ,
OA perpendicular PQ.
and ,
OB perpendicular LM
=> AB perpendicular PQ
and
AB perpendicular LM
=> Angle PAB = 90°
and ,
Angle ABM = 90°
=> Angle PAB = Angle ABM [ each 90°]
But these are alternate angles
so ,
PQ || LM
therefore the tangents drawn at the ends of a diameter of a circle are parallel.
proved
be brainly
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dannyfk:
cool
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