prove that the tangents drawn from the end of the diameter of a circle are always parallel
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Given:- CD and EF are the tangents at the end points A and B of the diameter AB of a circle center O.
To prove :- CD parallel to EF
Proof :- CD is the tangent to the circle at the point A .
Therefore,
CD perpendicular to OA= Angle OAD = 90 degree.
EF is the tangent to the circle at the point B.
Therefore,
EF perpendicular to OB = Angle OBE= 90 degree.= Angle ABE = 90 degree.
Thus,
Angle BAD = Angle ABE ( each equal to 90)
But these are alternate interior Angle.
Therefore,
CD parallel EF..
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MARK IT AS BRAINLEIST IF YOU LIKED THIS SOLUTION..
To prove :- CD parallel to EF
Proof :- CD is the tangent to the circle at the point A .
Therefore,
CD perpendicular to OA= Angle OAD = 90 degree.
EF is the tangent to the circle at the point B.
Therefore,
EF perpendicular to OB = Angle OBE= 90 degree.= Angle ABE = 90 degree.
Thus,
Angle BAD = Angle ABE ( each equal to 90)
But these are alternate interior Angle.
Therefore,
CD parallel EF..
HOPE IT WILL HELP YOU..
MARK IT AS BRAINLEIST IF YOU LIKED THIS SOLUTION..
Namit1111:
how we know that angel BAD and angel ABE are alternative angels
Answered by
1
Draw the diameter vertically
And tangents horizontally then 2angles would be 90 nd alternate
Hence 2tangents are parralel
And tangents horizontally then 2angles would be 90 nd alternate
Hence 2tangents are parralel
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