Prove that “The tangents drawn to a circle, from an external point are equal”.
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Step-by-step explanation:
QT is a tangent to the circle at T and OT is radius
∴ OT ┴ QT
Also, OQ = 25 cm
and QT = 24 cm
ncert
∴ Using Pythagoras theorem, we get
OQ2 = QT2 + OT2
⇒ OT2 = OQ2 - QT2 = 252 - 242 = 49
⇒ OT = 7
Thus, the required radius is 7 cm.
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