prove that the tangents drawn to an circle from an external point are equal
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Correct Question:-
Prove that length of tangents drawn from an external point to a Circle are equal.
Solution:-
Given :- Let circle Be with the centre O & P be a point outside the circle PQ & PR are two Tangents to circle intersecting at point Q & R respectively.
To prove:-
lengths of Tangents are equal
=> PQ = PR
Construction:-
Join OQ, OR & OP
OQ | PQ --( Tangent at any point of a circle is perpendicular to the radius through the point of contact)
So, ∠OQP = 90°
Hence , ∆ OPQ is right Triangle
Same as PR is a Tangent
& OR | PR
=> ∠ORP = 90°
Now, in ∆ OPQ & ∆ORP
- ∠OQP = ∠ORP ---(Both 90°)
- OP = OP ----(Common)
- OQ = OR ----(Radius)
- ∆OQP ~ ∆ORP ----( RHS Congruency)
- PQ = PR ( CPCT) Hence Proved!
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