prove that the tangents to acircle at the end point of a diameter are parallel
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Answer:
Let AB be a diameter of the circle. Two tangents PQ and RS are drawn at points A and B respectively. Radius drawn to these tangents will be perpendicular to the tangents. Since alternate interior angles are equal, lines PQ and RS will be parallel
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Step-by-step explanation:
we have a circle with centre O PA and PB are two tangents on circle,
join O to A and O to B and P to O,
NOW we have two triangles PBO and PAO,
by theorem 10.1 we know tangent to a circle is perpendicular to radius at point of contact,
so. angle OAP and OBP is 90,
now in triangle PBO and PAO,
OAP=OBP(90 EACH)
PO=PO(COMMON)
OPB=OPA(SAME RADII),
by RHS TRIANGLES ARE CONGRUENT, BY
CPCT PA=PB
THEREFORE PA II PB (CPCT),
HP
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