Question

prove that the target at any point of the circle is perpendicular to the radius the points of contact​

Answer 1

Step-by-step explanation:

Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is shortest to l. Now, OB = OC + BC. B is an arbitrary point on the tangent l. Thus, OA is shorter than any other line segment joining O to any point on l.