prove that the three lines 5x+3y-7=0,3x-4y=10,x+2y=0 meet in a point
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Answer:
x+2y=0
x=-2y
put the value of x = -2y
3x-4y=10
3(-2y) -4y=10
-6y-4y=10
-10y=10
y=10/-10
y=-1
again
5x+3y-7=0
5x+3(-1) -7=0
5x-3-7=0
5x-10=0
x=10/5
x=2
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