Question

Prove that the time period of a simple pendulum on the surface of moon is 2.45 times greater than on the surface of Earth .

Answer 1

Answer:

Explanation: On the surface of the moon, acceleration due to gravity is g/6. The time period of seconds pendulum on earth is 2 seconds.

On Earth, 2=2π

g

l

​

​

On the moon, T

moon

​

=2π 6gl

​

Dividing the above two equations, we get, T

moon

​

=2 6s