prove that the total energy at any point inthe path of a dropped mass is mg times the height from where it is dropped?
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Assume a object of mass m.
And it is raised to height h.
By this we know that the work is done against the gravity in raising a body to height h. And some force will be required to raise it to height h. As the weight is acting vertically downward so the force = mg and displacement will be height h.
Now we know,
Work = force * displacement
= mg * h
= mgh
Hence, The total energy at any point in the path of a dropped mass is mg * h from where it dropped and is known as Gravitational Potential Energy.
Hope It Helps You! ☺☻☺
Assume a object of mass m.
And it is raised to height h.
By this we know that the work is done against the gravity in raising a body to height h. And some force will be required to raise it to height h. As the weight is acting vertically downward so the force = mg and displacement will be height h.
Now we know,
Work = force * displacement
= mg * h
= mgh
Hence, The total energy at any point in the path of a dropped mass is mg * h from where it dropped and is known as Gravitational Potential Energy.
Hope It Helps You! ☺☻☺
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Gravitational potentially
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