Prove that the Triangle Law of vector addition analytically
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Triangle law of Vector addition
Let vector A and B be represented on the two sides of a triangle .(refer figure)
drop a perpendicular RS to PR
SP^2 = PR^2+SR^2
or, sp^2 = (A+QR)^2 + SR^2
In Triangle sqr
SR/B = sinQ
SR = BsinQ
similarly ,
QR/B = cosQ
QR = BcosQ
substituting in main equation
sp^2 = (A+BcosQ)^2 + (BsinQ)^2
R^2 = A^2 + 2ABCosQ + B^2CosQ^2 + B^2sinQ^2
R = √A^2 + B^2 + 2ABCosQ
tan P = sr/PR
or, tan P = BsinQ/(A+BcosQ)
ie, direction
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