prove that the two circle draw on the two equal sides of an isosceles triangle as diameter pass through the midpoint of third side
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Answer:
Construction : Join AD.
Proof : ∠ADB = 90˚ (Angle of semi-circle)
In △ABD & △ACD,
AB = AC (Given)
∠ADB = ∠ADC (90˚)
AD = AD (Common)
∴ △ABD ≅ △ADC
Hence BD = DC
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