Question

prove that the under root 13 an irrTinal coefficient
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Answer 1

Answer:

Hello mate!!!

Let us assume that √13 is rational no and equals to p/q are Co primes

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/q

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/p

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer r

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*213q*2=169*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*213q*2=169*2b*2=13r*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*213q*2=169*2b*2=13r*213/b*2

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*213q*2=169*2b*2=13r*213/b*213/b

Let us assume that √13 is rational no and equals to p/q are Co primes √13=p/qsquaring both sides √13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*213q*2=169*2b*2=13r*213/b*213/b13 is a common factor but this is contradiction hence our supposition is wrong √13 is irrational no