Math, asked by anusripatra87, 5 hours ago

prove that the value of ×2+y2+z2+xy+yz is 43 when x =4, y= -6 and z= 5​

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Answered by sugantipandit601
1

Answer:

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Answered by sugantipandit7
3

devindersaroha43. Genius. 2.4K answers. 569.1K ... x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx).

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