Math, asked by Shashwat16846, 12 hours ago

. Prove that the value of x² + y² + z²+ xy + yz + zx is 43 when x = 4, y = -6 and z = 5.

Answers

Answered by bandanamaity741
11

Answer:

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Step-by-step explanation:

L. H. S. : R. H. S. : 43

x² + y² + z² + xy + yz + zx

= (4)² + (-6)² + (5)² + (4 × -6) + (-6 × 5) + (5 × 4)

= 16 + 36 + 25 -24 - 30 + 20

= 97 - 54

= 43 = R. H. S.

SO, L. H. S. = R. H. S. (PROVED)

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