Question

prove that the vectors a=3i + 2j - 2k b=-i+3j+4k and c = 4i - j -6k can form a triangle ​

Answer 1

Answer:

Step-by-step explanation:

Concept used:

Triangle law of addition of vectors:

If two vectors are represented both magnitude and direction by two sides of a triangle then their sum is represented by third side of the triangle taken in the reverse order.

Given:

$\vec{a}=3\vec{i}+2\vec{j}-2\vec{k}$

$\vec{b}=-\vec{i}+3\vec{j}+4\vec{k}$

$\vec{c}=4\vec{i}-\vec{j}-6\vec{k}$

Now,

$\vec{b}+\vec{c}$

$=(-\vec{i}+3\vec{j}+4\vec{k})+(4\vec{i}-\vec{j}-6\vec{k})$

$=3\vec{i}+2\vec{j}-2\vec{k}$

$=\vec{a}$

Hence the given vectors form a triangle.

Answer 2

Answer:

a=3i + 2j - 2k b=-i+3j+4k and c = 4i - j -6k can form a triangle

Step-by-step explanation:

It is a vector