Question

prove that the velocity of the electron moving in the first orbit is twice that of the electron revolving in the second orbit of hydrogen atom

Answer 1

Velocity at nth orbit is v= (2.165 x10^6) x (Z/n)

actually v= (2( pi ^2)Km(e^2)Z )/(hn)

K= electrostatic constant

m= mass of electron

e= charge of electron

h= planks cnst

n= nth orbit

Z= atomic number

this simplifies to the top expression

so for 3rd orbit of hydrogen

v= (2.165x 10^ 6 )/ 3

v= x/3