Physics, asked by aziealie340, 11 months ago

Prove that the volume remains constant when the poisson ratio of a material is 0.5

Answers

Answered by vikasdeep84
1

Answer:

Explanation:

Solution :

Let L be the length, r be the radius of the wire.

Volume of the wire is

V=πr2L

Differentiating both sides, we get

△V=π(2r△r)L+πr2△L

As the volume of the wire remains uncharged when it gets stretched, so △V=0. Hence

0=2πrL△r+πr2△L

(△rr/(△LL)=−12

Poisson's ration

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