Question

Prove that there is no natural no.for which 4n & with the digit zero

Answer 1

If the number 4n ,for any n, were to to end with digit zero, then it would be divisible by 5.That is ,the prime factorisation of 4n would contain the prime 5.

Answer 2

For 4n to end with zero, 5 and 2 should be factors of 4n...

But 4n = (2 x 2) n = 2n x 2n

Therefore, 4n can never end with zero...

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