Question

Prove that there is no natural number for which 4n ends with the digit zero

Answer 1

consider ,
4={2x2}^n

therefore we know that a digit can be end with zero if it has 5 as factor . since 4^n has not 5 as factor so it can not end with zero

Answer 2

Step-by-step explanation:

→ No, 4ⁿ can never end with the digit 0 for any natural number n .

→ If 4ⁿ ends with 0 then it must have 5 as a factor .

But, 4ⁿ = ( 2² )ⁿ = 2²ⁿ .

→ It shows that 2 is the only prime factor of 4ⁿ .

Also, we know from the fundamental theorem of airthematic that the prime factorisation of each number is unique .

So, 5 is not a factor of 4ⁿ .

Hence, 4ⁿ can never end with the digit 0 .