Math, asked by dangerwizard8800, 4 months ago

Prove that thetangent at any point of a circle is parpendicular to the radius throug the point of contact

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Answered by amriteshkumar1970

Answer:

Suppose OB meets the circle in C. Proof: We know that, among all line segment joining the point O to a point on l, the perpendicular is shortest to l. ... B is an arbitrary point on the tangent l. Thus, OA is shorter than any other line segment joining O to any point on l.

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