prove that this equation is equal to 1 ... when abc=1
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abc=1
⟹c=1/ab
1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a)
=1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a)
=b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab)
=1+b+ab/(1+b+ab)!
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