Question

prove that this is irrational​

Answer 1

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Answer 2

AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• A term 6+√2
• where√2 is a irrational no

${\sf{\green{\underline{\large{To\:prove}}}}}$

• This is a irrational no

${\sf{\pink{\underline{\Large{Proof}}}}}$

Let 6+√2 is a rational no

Then this term must be in the form of a/b where b is not equal to 0

=>6+√2 = a/b

=>√2 = a/b - 6

=>√2 = (a-6b) / a

• Here a-6b /a is is a rational no then√2 be must be irrational

• But in given it is given that √2 is a irrational no

• Therefore our assumption is wrong

Hence 6+√2 is a irrational no