Question

Prove that three rimes the square of any side of an equilateral traingle is equal to four times the square of the altitude​

Answer 1

Answer:

this is your answer

Answer 2

Answer:3AB^2=4BC^2

Step-by-step explanation: let the sides of triangle be: a anthem the altitude perpendicular to the base divides it into to parts let it be a/2.

=AD=AC=a

BD=CD=a/2

BCis an altitude.

By Pythagoras theoram,

AB^2=BC^2+AC^2

(a^2) =(a/2^2) +BC^2

a^2=a^2/4+BC^2

a^2-a^2/4=BC^2

4a^2-a^2/4=BC^2

3a^2/4=BC^2

(as a is the one of sides of )

3AB^2=4BC^2