prove that "three times of any side of an equilateral triangle is equal to four times the squares of the altitude?"
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Answered by
5
let x be the side of the equilateral triangle.
then altitude = x√3 / 2
4 times altitude = 4 × (x√3 / 2)^2
= 4 × (3x^2 / 4)
= 3x^2
= 3 times the square of side.
then altitude = x√3 / 2
4 times altitude = 4 × (x√3 / 2)^2
= 4 × (3x^2 / 4)
= 3x^2
= 3 times the square of side.
Answered by
7
See diagram.
Use Pythagoras theorem in the right angle triangle ADC.
AC² = AD² + DC²
a² = h² + (BC/2)² a² = h² + a² / 4
h² = a² - a²/4 = 3a²/4
4 h² = 3 a²
Use Pythagoras theorem in the right angle triangle ADC.
AC² = AD² + DC²
a² = h² + (BC/2)² a² = h² + a² / 4
h² = a² - a²/4 = 3a²/4
4 h² = 3 a²
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prabhushettisan:
sir ho you got a2-a2/4=3a2/4
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