prove that three times the square if any side of sn epquilateral triangle is equal to four times the square of the altitude
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Answer:
➡ Given :-
→ A ∆ABC in which AB = BC = CA and AD BC .
➡ To prove :-
→ 3AB² = 4AD².
➡ Proof :-
In ∆ADB and ∆ADC, we have
→ AB = AC. [ Given ]
→ B = C = 60° .
→ ADB = ADC = 90° .
•°• ∆ADB ∆ADC . [ AAS - Congruence ]
•°• BD = DC = ½BC .
▶ From right ∆ADB, we have
AB² = AD² + BD² . [ By Pythagoras' theorem ]
= AD² + ( ½ BC )² .
= AD² + ¼ BC² .
=> 4AB² = 4AD² + BC² .
=> 3AB² = 4AD² . [ °•° BC = AB ] .
✔✔ Hence, 3AB² = 4AD²
Hope it helps you my dear friend..
nithya6755:
Good
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