Question

Prove That Time of Ascent is equal to time of descent.​

Answer 1

Explanation:

During Ascent g=9.8, t1=time taken for ascent,u=initial velocity, v= final velocity=0

therefore t1=(v - u)/g=u/g

during descent,

g=9.8 , u= initial velocity 0, v= final velocity, t2 = time taken for descent

therefore, t2=(v-u)/g =(v-0)/g

the velocity with which the body is thrown= the velocity with which body hits the ground.

therefore, u/g= v/g

So, t1=t2

Hence, time of ascent=time of descent (proved)

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