Question

Prove that time of flight T and horizontal range of a projectile are connected by an equation GT^2=2R tan tita

Answer 1

Answer:

gT² = 2RTanθ

Explanation:

Angle of Projection = θ

Let say Velocity = V

Vertical Velocity = VSinθ

Velocity at Max Height = 0

Using V = U + at

=> 0 = VSinθ - gT

=> T =  VSinθ/g

Same time to return to Ground

so Flight Time = 2VSinθ/g

T = 2VSinθ/g

=> V = gT/2Sinθ

Horizontal Range = Horizontal Velocity * Flight Time

=> R = VCosθ  * T

=> R = Cosθ(gT/2Sinθ) * T

=>  2R = gT²/Tanθ

=> gT² = 2RTanθ

Answer 2

Answer:

Explanation answer