prove that tri. ADE is similar to tri. ABC
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angle D=angleB
an.1=an.3(corresponding interior angle)
similarly,
an.E=an.C
an.2=an.4
tr.FEC=tr.GBD(given)
so,BD=DC
ln triangle(ABC)and in triangle(ADE)
AD=BD
AE=AC
DE=BC(base)
an.1=an.2(co interior angle)
an.3=an.4(co interior angle)
AD=1/2ABand AE =1/2AC
means,
2AD=AB,2AE=AC
AB=AC,AD=AC,BD=EC
tr. AED=tr. ABC
tr. AED~=~tr.ABC
and FG is other line
where BC is the base of triangle ABC and
FB And CG is other
an.1=an.3(corresponding interior angle)
similarly,
an.E=an.C
an.2=an.4
tr.FEC=tr.GBD(given)
so,BD=DC
ln triangle(ABC)and in triangle(ADE)
AD=BD
AE=AC
DE=BC(base)
an.1=an.2(co interior angle)
an.3=an.4(co interior angle)
AD=1/2ABand AE =1/2AC
means,
2AD=AB,2AE=AC
AB=AC,AD=AC,BD=EC
tr. AED=tr. ABC
tr. AED~=~tr.ABC
and FG is other line
where BC is the base of triangle ABC and
FB And CG is other
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