Prove that triangle ABC is an isosceles triangle if median AD bisectsBC
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HEY MATE,
GIVEN : IN ΔABC. AD IS MEDIAN BISECT BC SO BD=DC.
TO PROVE = ΔABC IS ISOSCELES.
PROOF = IN Δ ABD AND Δ ADC
AD = AD -{ COMMON }
BD = DC. -{ GIVEN }
ANGLE ADB = ANGLE ADC -{EACH 90°}
THEREFORE, ΔABD =~ ΔADC -{ SAS }
SO, AB = BC -{C. P. C. T}
SO, ΔABC IS ISOSCELES.
I HOPE THIS WILL HELP YOU...
PLS MARK AS BRAINLIEST.
GIVEN : IN ΔABC. AD IS MEDIAN BISECT BC SO BD=DC.
TO PROVE = ΔABC IS ISOSCELES.
PROOF = IN Δ ABD AND Δ ADC
AD = AD -{ COMMON }
BD = DC. -{ GIVEN }
ANGLE ADB = ANGLE ADC -{EACH 90°}
THEREFORE, ΔABD =~ ΔADC -{ SAS }
SO, AB = BC -{C. P. C. T}
SO, ΔABC IS ISOSCELES.
I HOPE THIS WILL HELP YOU...
PLS MARK AS BRAINLIEST.
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pls mark as BRAINLIEST
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